2 Al + Fe\(_2\)O\(_3\) \(\longrightarrow\) Al\(_2\)O\(_3\) + 2 Fe
An operation requires at least 86.0 g of Fe to be produced. What is the minimum mass in grams of Fe\(_2\)O\(_3\) necessary to produce the desired amount of products? How much Al\(_2\)O\(_3\) is produced as a side product?
MM of Fe\(_2\)O\(_3\) = 159.489 g/mol
MM of Al\(_2\)O\(_3\) = 101.961 g/mol